The body, thrown vertically upwards, reached a height of 27m. At what altitude was the speed

The body, thrown vertically upwards, reached a height of 27m. At what altitude was the speed of the body 3 times less than the initial speed?

Distance traveled by the body:

S = (V² – V0²) / 2a, where S is the distance traveled by the body (S = 27 m), V is the final speed of the body, V0 is the initial speed of movement, and is the acceleration of the body (a = g, g is the acceleration of gravity (we take g = 9.8 m / s²)).

At maximum height:

V = 0, S = 27 m.

S = (V² – V0²) / 2a.

27 = – V0² / (2 * 9.8).

V0² = 27 * 20 = 540.

V0 = sqrt (540) = 23 m / s.

When V = 1 / 3V0 = 7.67 m / s:

S = (V² – V0²) / 2g = (7.672 – 232) / (2 * 9.8) = 24 m.