The body vibrates first at a frequency of 6 Hz, and then at a frequency of 4 Hz

The body vibrates first at a frequency of 6 Hz, and then at a frequency of 4 Hz, exciting waves in the water. Compare the wavelengths propagating in the water.

To compare the wavelengths of the obtained waves propagating in water, we use the formula: k = λ2 / λ1 = (V / ν2) / (V / ν1) = ν1 / ν2.

Values of variables: ν1 – frequency of the first wave (ν1 = 6 Hz); ν2 is the frequency of the second wave (ν2 = 4 Hz).

Let’s perform the calculation: k = ν1 / ν2 = 6/4 = 1.5 p.

Answer: The length of the second received wave is 1.5 times longer.



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