The body was thrown at a 45 ° angle. What will be the ratio of the velocities at the moment

The body was thrown at a 45 ° angle. What will be the ratio of the velocities at the moment of throwing and at the highest point of the body’s trajectory?

To find the required ratio of the velocities of the thrown body at the considered points of the trajectory, we will use the formula: k = V0 / V0x = V0 / (V0 * cosα) = 1 / cosα.

Values of variables: α – body throw angle (α = 45º).

Let’s calculate: k = 1 / cosα = 1 / cos 45º ≈ 1.4 p.

Answer: At the moment of the throw, the body had a speed of 1.4 times more.