The body was thrown at an angle of 60 degrees to the horizon at a speed of 20 m / s.

The body was thrown at an angle of 60 degrees to the horizon at a speed of 20 m / s. At what height will the body’s speed be directed horizontally.

To find the height at which the total velocity of the thrown body should be directed horizontally (maximum lifting height), we will use the formula: h = V0 ^ 2 * sin2α / 2g.

Variables and constants: V0 – throw speed (V0 = 20 m / s); α – throw angle (α = 60º); g – acceleration due to gravity (g ≈ 10 m / s2).

Calculation: h = V0 ^ 2 * sin2α / 2g = 20 ^ 2 * sin2 60º / (2 * 10) = 15 m.

Answer: The full speed of the thrown body will be directed horizontally at a height of 15 m.