The body was thrown at an angle to the horizon from a height of 2 m and a speed of 10 m / s. Determine the speed

The body was thrown at an angle to the horizon from a height of 2 m and a speed of 10 m / s. Determine the speed of the body at the highest point of ascent, equal to 5 m.

Given: h = 2m, H = 5m, v0 = 10m / s
Find: v =?
Decision :
From a point with a value of 2m, the body moved to a point with a value of 5, which means that only Hm = 3 m passed (5m-2m)
At the maximum value, the following formula is used:
Hm = gt ^ 2, where Hm is the maximum flight altitude
3 = 10 * t ^ 2
0.3 = t ^ 2
t = 0.55s
At the highest point of ascent Vy = 0 (speed along the OY axis) always, and since the body does not move along the OX axis, the speed at this moment is zero.
Answer: speed is zero.