The body was thrown from a height of 5 m with an initial velocity of 5 m / s directed upwards. There is no air resistance.

The body was thrown from a height of 5 m with an initial velocity of 5 m / s directed upwards. There is no air resistance. The body falls to Earth at a speed …?

If thrown up at a right angle, then all the kinetic energy with which the body was thrown up will go first into potential, and then back into kinetic, but in the direction we need. Moreover, since there is no resistance, then we will not lose speed.
Simply put, when the stone begins to fall and the place from which it was thrown will fly by, it will have the same speed with which it was thrown up, but already directed towards the ground.
there remains the speed that the body will pick up by falling these 5 m
kept by law. energy
En = Ek
mgh = mv ^ 2/2
2gh = v ^ 2
v = √ (2gh)
v = √ (2 * 9.8 * 5) = 9.9 m / s
the final speed will be equal to Vo + V = 9.9 + 5 = 14.9 m / s