The body was thrown horizontally at a speed of 10 m / s. Determine the speed of the body 1 s

The body was thrown horizontally at a speed of 10 m / s. Determine the speed of the body 1 s after the start of movement, if at this moment the body has not yet reached the earth’s surface.

To find the full speed of a horizontally thrown body after 1 second of falling, we will use the formula: V = √ (Vv ^ 2 + Vg ^ 2) = √ ((g * t) ^ 2 + Vg ^ 2).

Constants and variables: g – gravitational acceleration (g ≈ 10 m / s2); t is the duration of the fall (t = 1 s); Vg – horizontal throw speed (Vg = 10 m / s).

Let’s perform the calculation: V = √ ((g * t) ^ 2 + Vg ^ 2) = ((10 * 1) ^ 2 + 10 ^ 2) = 14.14 m / s.

Answer: After 1 s of the fall, the speed of the thrown body became equal to 14.14 m / s.