The body was thrown horizontally from a height of 20 m at a speed of 30 m / s.

The body was thrown horizontally from a height of 20 m at a speed of 30 m / s. How long did it fall? How far did it fly? And what is the speed of the body when it falls?

Given:
h initial = 20m;
V initial = 30m / s;
Find: t fall, S, V at the moment of fall?
Decision:
We use this formula:
S = V initial * t fall.
t fall = √ 2h initial / g = √40 / 10 = √4 = 2 s.
Then S = Vsat * t = 30 * 2 = 60m.
Next, let’s find the speed.
Vx = Vsat = 30m / s
Vy = -gt = -20m / s
V any point = √ (Vx ^ 2 + Vy ^ 2) = √ 900 + 400 = 36m / s.
Answer: t fall = 2; S = 60 m; V = 36 m / s.