# The body was thrown up from the ground at a speed of 4 m / s. At what height will its potential

December 26, 2020 | education

| **The body was thrown up from the ground at a speed of 4 m / s. At what height will its potential and kinetic energies become the same?**

Given:

V initial = 4.9 m / s;

g = 10 m / s ^ 2;

Ep (potential energy) = Ek (kinetic energy).

Find: height h

Decision:

We will use the law of conservation of mechanical energy. It follows from it that:

Eko = Ep + Ek = 2Ep.

We use the formulas for kinetic and potential energies:

Eko = mvstart ^ 2/2 and Ep = mgh.

Substitute the right-hand sides of these formulas into the formula we wrote in the first paragraph. And we get:

mv start ^ 2/2 = 2mgh.

From here we express the h to be found.

h = v start ^ 2 / 4g.

We substitute the values that are known and find the answer:

h = 4.9 ^ 2/4 * 9.8 = 0.6 meters.

Answer: 0.6

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