The body was thrown up from the ground at a speed of 4 m / s. At what height will its potential

The body was thrown up from the ground at a speed of 4 m / s. At what height will its potential and kinetic energies become the same?

Given:
V initial = 4.9 m / s;
g = 10 m / s ^ 2;
Ep (potential energy) = Ek (kinetic energy).
Find: height h
Decision:
We will use the law of conservation of mechanical energy. It follows from it that:
Eko = Ep + Ek = 2Ep.
We use the formulas for kinetic and potential energies:
Eko = mvstart ^ 2/2 and Ep = mgh.
Substitute the right-hand sides of these formulas into the formula we wrote in the first paragraph. And we get:
mv start ^ 2/2 = 2mgh.
From here we express the h to be found.
h = v start ^ 2 / 4g.
We substitute the values that are known and find the answer:
h = 4.9 ^ 2/4 * 9.8 = 0.6 meters.
Answer: 0.6