The body was thrown up, giving it a speed of 8 m / s. To what height will the body rise?

These tasks: V (the speed that was given to the taken body when thrown upwards) = 8 m / s.

Reference values: g (acceleration due to gravity) ≈ 10 m / s2.

Method 1) The law of conservation of energy: m * g * h = m * V ^ 2/2 and h = m * V ^ 2 / (2 * m * g) = V ^ 2 / (2 * g) = 8 ^ 2 / (2 * 10) = 64/20 = 3.2 m.

Method 2) Formula for the distance traveled: S = (Vk ^ 2 – V ^ 2) / 2a = (0 – V ^ 2) / (2 * (-g)) = V ^ 2 / (2 * g) = 3 , 2 m.

Answer: The taken body will be able to rise to a height of 3.2 m.