The body was thrown vertically down from a height of 15 m, with an initial speed of 3.7 m / s, write down the equations

The body was thrown vertically down from a height of 15 m, with an initial speed of 3.7 m / s, write down the equations of motion (speed, coordinates, displacement)

The general equation of motion of a body thrown down with some initial velocity looks like this:
S = V0 * t + (g * t2) / 2.
in this case V0 = 3.7 m / s, g = 9.8 m / s2, S = 15m.
15 = 3.7 + 9.8 * t2 / 2. From here you can find the time t after which the body reaches the earth.
As for the coordinates. Initial coordinate Y = 15 – body height above the ground.
The final coordinate Y = 0. Along the X coordinate, no changes occur during the vertical movement of the body.