The body was thrown vertically upward. At a height of 10 M, its kinetic energy became equal

The body was thrown vertically upward. At a height of 10 M, its kinetic energy became equal to potential. How fast was the body thrown?

To find the speed with which it was necessary to throw a given body, we will use the equality (the law of conservation of energy): En1 + Ek1 = 2En = Ek0; 2 * m * g * h = m * V0 ^ 2/2, whence we express: V0 = √ (2 * 2 * g * h) = √ (4 * g * h).

Constants and variables: g – gravitational acceleration (g ≈ 10 m / s2); h is the considered lift height (h = 10 m).

Calculation: V0 = √ (4 * g * h) = √ (4 * 10 * 10) = 20 m / s.

Answer: The body throwing speed was 20 m / s.