The body was thrown vertically upward at a speed of 25 m / s.

The body was thrown vertically upward at a speed of 25 m / s. Determine the distance traveled by the body in meters until it hits the Earth. Disregard air resistance.

To find the path traversed by the thrown body until the moment it falls, we will use the formula: S = h1 + h2 = 2h1 = 2 * (Vk ^ 2 – Vn ^ 2) / 2a = (Vn ^ 2 – 0 ^ 2) / g = Vn ^ 2 / g.

Variables and constants: Vн – speed at the moment of throw (Vн = 25 m / s); g – acceleration due to gravity (g ≈ 10 m / s2).

Calculation: h = Vn ^ 2 / g = 25 ^ 2/10 = 62.5 m.

Answer: The path from the moment of throwing the taken body to the moment of falling is 62.5 m.



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