The body was thrown vertically upward with an initial speed of 14 m / s

| February 17, 2021 | education

The body was thrown vertically upward with an initial speed of 14 m / s, which will be the speed in 2.3 seconds. At what height will the body be at these moments in time.

Task data: V (vertical throw up speed) = 14 m / s; t1 (first considered time) = 2 s; t2 (second considered time) = 3 s.

Constants: g (acceleration due to gravity) ≈ 10 m / s2.

1) Height at the first moment in time: h1 = V0 * t1 – g * t1 ^ 2/2 = 14 * 2 – 10 * 2 ^ 2/2 = 8 m (the body reached its maximum height (9.8 m) and began to fall ).

2) Altitude at the second moment of time: h2 = V0 * t ^ 2 – g * t2 ^ 2/2 = 14 * 3 – 10 * 3 ^ 2/2 = -3 m = 0 m (the body fell back, the flight lasted 2 , 8 s).

Answer: After 2 seconds the body was at a height of 8 m; after 3 s – at a height of 0 m.



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