The body was thrown vertically upward with an initial speed of 90 km / h. What is the maximum lifting height and body speed in 2 s.

Ball speed:
V = V0 – g * t1, where V is the speed of the body at maximum height (V = 0 m / s), V0 is the initial speed of the body (V0 = 90 km / h = 90 * 1000/3600 s = 25 m / s) , g – acceleration of gravity (g = 10 m / s²), t1 – time of body lifting.
V0 = g * t1.
t1 = V0 / g = 25/10 = 2.5 s.
Distance traveled:
S = V0 * t – g * t² / 2 = 25 * 2.5 – 10 * 2.5² / 2 = 62.5 – 31.25 = 31.25 m.
Body speed in 2 s:
V = V0 – g * t = 25 – 10 * 2 = 5 m / s.
Answer: Max. the lifting height is 31.25 m, the speed of the body in 2 s is 5 m / s.