The body weight is 4.5 N, and its volume is 500 cm3. Will this body drown in water? alcohol? kerosene?

Body weight P = 4.5 N, its volume V = 500 cm3, water density ρ = 1000 kg / m3, alcohol density and kerosene density ρ = 800 kg / m3.

To answer the question whether the body will drown in these fluids, you need to compare the density of the body and the density of the fluid. Let’s convert the volume to the SI system:

500 cm3 = 500 * (1/100) ^ 3 m3 = 0.0005 m3.

From the formula for body weight, we find its mass:

P = m * g, hence m = P / g = 4.5 N / (10 N / kg) = 0.45 kg.

Now let’s find the density of the body:

ρ = m / V = ​​0.45 kg / (0.0005 m3) = 900 (kg / m3).

Now you can see that the density of the body is less than the density of water, so it will not sink in water.

And since the density of the body is greater than the density of kerosene and alcohol, therefore, it will sink in these liquids.

Answer: in alcohol and kerosene the body will drown, in water – no