The boiler is connected to a network with a voltage of 220 V. What is the current strength in the spiral of an electric boiler

The boiler is connected to a network with a voltage of 220 V. What is the current strength in the spiral of an electric boiler, if it is made of nichrome wire 5 m long and a cross-sectional area of 0.1 mm2.

U = 220 V.

L = 5 m.

S = 0.1 mm2.

ρ = 1.1 Ohm * mm2 / m.

I -?

The current strength in the nichrome wire I is directly proportional to the voltage at its ends U and inversely proportional to the resistance of this wire R: I = U / R.

Since the conductor has a homogeneous structure, its resistance R is expressed by the formula: R = ρ * L / S, where ρ is the resistivity of the wire material, L is the length of the wire, S is the cross-section of the wire.

I = U * S / ρ * L.

Since the wire of the electric boiler is made of nichrome, its resistivity is ρ = 1.1 Ohm * mm2 / m.

I = 220 V * 0.1 mm2 / 1.1 Ohm * mm2 / m * 5 m = 4 A.

Answer: current strength I = 4 A passes through the nichrome wire of the electric boiler.