The book has 130 pages, each page contains 80×40 characters. Can this book be burned onto a 1.44 megabyte floppy disk?

Let’s find the number of characters in the book: 130 * 80 * 40 = 416,000 characters. In standard encoding, 1 character is encoded in one byte. Therefore 416,000 characters = 416,000 bytes 1 kbyte = 1024 bytes => 416,000 bytes / 1024 = 406.25 kbytes 1 mbyte = 1024 kbytes => 406.25 kbytes / 1024 = 0.39 mbytes 0.39 mbytes <1, 44 MB
Answer: Yes