The book typed by the computer contains 1024 pages on each page 64 lines in each line 25 characters determine

The book typed by the computer contains 1024 pages on each page 64 lines in each line 25 characters determine the information volume of the book in Mbit in one of the Unicode encodings in which each character is encoded in 16 bits.

Let’s find the total number of characters in this book:
1) 1024 * 64 * 25 = 1664000 (pcs.) – characters in the book.
Let’s find the information volume of the book in Unicode encoding:
2) 1664000 * 16 = 26624000 (bit) – informational volume of the book.
Let’s convert from bits to megabits, for this we first convert to kilobits:
3) 26624000: 1024 = 26000 (kbit) – informational volume of the book.
And then we will translate into megabits:
4) 26000: 1024 = 25.39065 (Mbps) – information volume of the book.
Answer: 25.39065.