The bottom of the pool has the shape of a rectangle, the length of which is 5 times

The bottom of the pool has the shape of a rectangle, the length of which is 5 times its width and the width is 200 meters less than its length. How many 20cm square ceramic tiles will it take to cover the bottom of this pool?

Let’s take the width of the pool equal to x m, and the length to y.

1. Equations based on the condition:

1) y = 5x,

2) y – 200 = x.

2. Substitute the value of y from the 1st equation into the 2nd and find x:

5 x – 200 = x,

5 x – x = 200,

4 x = 200,

x = 200: 4,

x = 50 m – the width of the pool.

3. Determine the length y:

y = 5 * x = 5 * 50 = 250 m.

4. Basin bottom area:

250 * 50 = 12,500 m ^ 2.

5. The area of one ceramic tile:

in 1 m – 100 cm, 20 cm – 0.2 m,

0.2 * 0.2 = 0.04 m ^ 2.

6. Calculate the number of tiles required:

12500: 0.04 = 312500 pieces.

Answer: You will need 312,500 tiles to cover the bottom of the pool.