The box with parts weighs 500 N. How much force is required to move

The box with parts weighs 500 N. How much force is required to move this box evenly across the horizontal floor if the friction force is 0.05 of the box weight?

P = 500 N.

Ftr = 0.05 * R.

F -?

According to 1 Newton’s law, a body can be in a state of rest or uniform rectilinear motion, if other forces do not act on it or the action of forces is compensated.

In the vertical direction, the box is acted upon by the force of gravity m * g and the reaction force of the support N, which compensate each other.

N = m * g.

For uniform rectilinear movement of the box horizontally in the direction of the force F, with which the box is pulled, must be compensated by the friction force Ffr: F = Ffr.

F = 0.05 * P.

F = 0.05 * 500 N = 25 N.

Answer: a force F = 25 N. must be applied to the box.