The boy evenly raised the bucket of water from the well once in 20 seconds and another in 30 seconds.

The boy evenly raised the bucket of water from the well once in 20 seconds and another in 30 seconds. Was the same work done in these cases? What can you say about the power when performing these works?

1) The work performed by the boys in question is the same, since with a uniform rise of buckets of water, the work performed corresponds to a change in their potential energies: A = ΔEp = m * g * h (m is the mass of the bucket (the same); g is the acceleration of gravity (const) ; h – well depth (same)).

2) The power that the boys developed is directly proportional to the work done and inversely proportional to the time spent by the boys: N = A / t. Since tm1 <tm2, the power of the first boy is greater: Nm1 / Nm2 = tm2 / tm1 = 30/20 = 1.5 times.