The boy on the balcony let go of the pebble, and after 0.5 seconds. – the ball.

The boy on the balcony let go of the pebble, and after 0.5 seconds. – the ball. What is the speed relative to the ball in another 0.5 seconds?

The velocity vector of the pebble and the velocity vector of the ball are directed in one direction and their relative velocity is calculated by the formula:

V (1,2) = V2 – V1, where V2 is the speed of the pebble, V1 is the speed of the ball.

At time t = 0.5 s.

V2 = V0 + a * t = 0 + g * t = 10 * 0.5 = 5 m / s.

V1 = 0 m / s.

V (1,2) = V2 – V1 = 5 – 0 = 5 m / s.

At time t = 1 s.

V2 = V0 + a * t = 0 + g * t = 10 * 1 = 10 m / s.

V1 = V0 + a * t = 0 + g * t = 10 * 0.5 = 5 m / s.

V (1,2) = V2 – V1 = 10 – 5 = 5 m / s.