The boy pulls the sled by the rope with a force of 50 N. Having walked 100 m with the sled, he completed

The boy pulls the sled by the rope with a force of 50 N. Having walked 100 m with the sled, he completed the work of 2500 J. What is the angle between the rope and the road?

F = 50 N.

A = 2500 J.

S = 100 m.

∠α -?

Mechanical work And when the boy moves the sled, we express the formula: A = F * S * cosα, where F is the force with which the boy pulls the sled, S is the movement of the sled under the boy’s action, ∠α is the angle between the direction of the boy’s force and the movement of the sled …

cosα = A / F * S.

cosα = 2500 J / 50 N * 100 m = 0.5.

According to the table of sines and cosines, we see that the value of this cosine corresponds to the angle ∠α = 60 °.

Answer: the rope by which the boy pulls the sled is ∠α = 60 ° with the horizon.