The boy rode a bicycle at a speed of 24 km / h, and then walked at a speed of 4 km / h, what part of the entire path
The boy rode a bicycle at a speed of 24 km / h, and then walked at a speed of 4 km / h, what part of the entire path and what part of the entire time of movement did the boy ride if he covered 16 km in 2 hours?
Vv = 24 km / h.
Vp = 4 km / h.
t = 2 h.
S = 16 km.
Sv / S -?
Since the boy covered the distance S in time t, he moved with an average speed Vav = S / t.
Vav = 16 km / 2 h = 8 km / h.
The time of the boy’s entire movement, t, will be the sum of the cycling time tв and the walking time tп: t = tв + tп.
Cycling time is expressed by the formula: tv = Sv / Vv.
The time of movement on foot tp is expressed by the formula: tp = Sp / Vp = (S – Sv) / Vp.
t = Sv / Vv + (S – Sv) / Vp.
t = (Sv * Vp + (S – Sv) * Vv) / Vv * Vp.
Sv * Vp + (S – Sv) * Vv = Vv * Vp * t.
Sv * Vp + S * Vv – Sv * Vv = Vv * Vp * t.
Sv * Vp – Sv * Vv = Vv * Vp * t – S * Vv.
Sv = Vv * (Vp * t – S) / (Vp – Vv).
Sw = 24 km / h * (5 km / h * 2 h – 16 km) / (4 km / h – 24 km / h) = 7.2 km.
Sw / S = 7.2 km / 16 km = 0.45.
Answer: 45% of the whole way the boy rode a bicycle, 55% walked: Sv / S = 0.45.