The boy rotates a stone on a rope with a length of 1.2 m. Determine the period of revolution of the stone

| August 16, 2021 | education

The boy rotates a stone on a rope with a length of 1.2 m. Determine the period of revolution of the stone if its average speed is 18 km / h

L = 1.2 m.

V = 18 km / h = 5 m / s.

T – ?

The period of rotation of the stone T on the rope is the time of one complete revolution. To find the time of movement t, it is necessary to divide the path S traversed by the stone by the speed of its movement V: t = S / V. During the time t. equal to the period T, the stone makes one complete revolution, that is, it traverses the path S equal to the circumference. The circumference S is determined by the formula: S = 2 * P * L, where L is the radius of the circle, in our case the length of the rope.

T = 2 * п * L / V.

T = 2 * 3.14 * 1.2 m / 5 m / s = 1.5 s.

Answer: the period of rotation of the stone is T = 1.5 s.



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