The boy slides down the snow slide with uniform acceleration. The speed of the sled at the end of the descent is 10 m / s. The acceleration is 1 m / s ^ 2 the initial speed is zero. The length of the slide is?
V = 10 m / s.
a = 1 m / s2.
V0 = 0 m / s.
When moving with constant acceleration, the path S traversed by the body is determined by the formula: S = V0 * t + a * t ^ 2/2, where V0 is the initial speed of the movement, t is the time of movement, a is the acceleration during movement.
Since the sled begins to move from a state of rest V0 = 0 m / s, the formula will take the form: S = a * t ^ 2/2.
The descent time t is expressed from the formula for acceleration a: a = (V – V0) / t.
t = (V – V0) / a.
t = V / a.
t = 10 m / s / 1 m / s2 = 10 s.
S = 1 m / s2 * (10 s) ^ 2/2 = 50 m.
Answer: the slide has a length of S = 50 m.
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