The boy slides down the snow slide with uniform acceleration. The speed of the sled at the end of the descent is 10 m / s.

The boy slides down the snow slide with uniform acceleration. The speed of the sled at the end of the descent is 10 m / s. The acceleration is 1 m / s ^ 2 the initial speed is zero. The length of the slide is?

V = 10 m / s.

a = 1 m / s2.

V0 = 0 m / s.

S -?

When moving with constant acceleration, the path S traversed by the body is determined by the formula: S = V0 * t + a * t ^ 2/2, where V0 is the initial speed of the movement, t is the time of movement, a is the acceleration during movement.

Since the sled begins to move from a state of rest V0 = 0 m / s, the formula will take the form: S = a * t ^ 2/2.

The descent time t is expressed from the formula for acceleration a: a = (V – V0) / t.

t = (V – V0) / a.

t = V / a.

t = 10 m / s / 1 m / s2 = 10 s.

S = 1 m / s2 * (10 s) ^ 2/2 = 50 m.

Answer: the slide has a length of S = 50 m.