The boy stands on the floor scales in the elevator. the lift starts moving upward with an acceleration of 1 m / s ^ 2.

The boy stands on the floor scales in the elevator. the lift starts moving upward with an acceleration of 1 m / s ^ 2. Determine what the scales will show during this movement, if they showed 40kg in a resting elevator.

Given:

m = 40 kilograms – the boy’s weight, measured in a resting elevator;

a = 1 m / s ^ 2 – the acceleration with which the elevator moves upward;

g = 10 m / s ^ 2 – acceleration of gravity.

It is required to determine the readings of the scales when the lift m2 is moving.

Since, according to the condition of the problem, the elevator moves up, then:

P = m * (g + a) = 40 * (10 + 1) = 40 * 11 = 440 Newton.

Since the scales show weight in kilograms, then:

m2 = P / g = 440/10 = 44 kilograms.

Answer: When the elevator is moving, the scale will show a weight of 44 kilograms.