The braking distance of the train is 150 m, the braking time is 30 s, find the initial speed of the train and its acceleration.
| February 28, 2021 | education
To find the initial speed of the train and its acceleration during braking, we use the formulas: S = Vn * t / 2, whence Vn = 2S / t and a = Vn / t.
Variables: S – braking distance (S = 150 m); t – braking time (t = 30 s).
Calculation: a) Initial speed: Vн = 2S / t = 2 * 150/30 = 10 m / s;
b) Acceleration: a = Vn / t = 10/30 = 0.33 (3) m / s2.
Check: S = Vn ^ 2 / 2a = 10 ^ 2 / (2 * 0.33 (3)) = 150 m (correct).
Answer: The initial speed of this train is 10 m / s; acceleration – 0.33 (3) m / s2.
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