The bullet flew horizontally from the muzzle at a speed of 1000 m / s. How much will the bullet’s height above

The bullet flew horizontally from the muzzle at a speed of 1000 m / s. How much will the bullet’s height above the horizon change when it reaches the target at a distance of 750 m?

Given:

v = 1,000 m / s;

S = 750 meters.

Let’s start the solution by finding the time it takes for a bullet to travel 750 meters at a speed of 1,000 m / s.

Let’s apply the speed formula:

v = S / t;

Let us express the time from it and get:

t = S / v;

Substitute the values and calculate:

t = 750/1000 = 0.75 seconds.

Let us find the distance at which the bullet will fall in 0.75 seconds, under the influence of gravity.

We use the formula:

H = (g * t ^ 2) / 2;

g = 9.8 m / s.

We substitute the values into the formula and perform the calculation:

H = (9.8 * 0.75 ^ 2) / 2 = 2.75625 m.