The bullet pierced the wall 20 cm thick, the speed in front of the wall was 600 m / s

The bullet pierced the wall 20 cm thick, the speed in front of the wall was 600 m / s and after the wall 300 m / s. With what acceleration the bullet moved inside the wall.

To calculate the acceleration of a given bullet inside the wall, we apply the formula: a = (V2 ^ 2 – V1 ^ 2) / 2S = (V2 ^ 2 – V1 ^ 2) / 2h.

Values of variables: V2 – velocity after the wall (V2 = 300 m / s); V1 – speed in front of the wall (V1 = 600 m / s); h – wall thickness, bullet path (h = 20 cm; in SI h = 0.2 m).

Let’s make a calculation: a = (300 ^ 2 – 600 ^ 2) / (2 * 0.2) = -675,000 m / s2 or -675 km / s2.

Answer: Inside the wall, the target bullet moved with an acceleration of -675 km / s2.