The bus and the truck, whose speed is 19 km / h more than the speed of the bus, drove out simultaneously towards
The bus and the truck, whose speed is 19 km / h more than the speed of the bus, drove out simultaneously towards each other from two cities, the distance between which is 620 km. Find the speed of the bus and truck if it is known that they met 4 hours after leaving.
let’s take the bus speed for x km / h. the time of his journey is 4 hours, then the entire path that he traveled is 4x (according to the formula S = ut). the speed of the truck is x + 19 km / h, the travel time is also 4 hours, and the entire journey is 4 * (x + 19). in total, both the car and the truck traveled 620 km. adding the two resulting expressions and equating them to 620, we can find x:
4x + 4 * (x + 19) = 620
4x + 4x + 76 = 620
8x = 544
x = 68 km / h – bus speed.
truck speed = 68 + 19 = 87 km / h
Answer: 68 and 87 km / h