The bus, being at a distance of 100 meters from the intersection, begins to move away from

The bus, being at a distance of 100 meters from the intersection, begins to move away from it with an acceleration of 1 m / s2. Where will the bus be in 6 seconds?

S1 = 100 m.

a = 1 m / s2.

t = 6 s.

S -?

The distance from the intersection to the bus S will be the sum: S = S1 + S2, where S2 is the distance that the bus will travel when moving in time t.

Since the bus was moving uniformly, its path S2 is expressed by the formula: S2 = V0 * t + a * t ^ 2/2, where V0 is the initial speed of the bus, a is the acceleration of the bus.

Since the bus began its movement from a state of rest V0 = 0 m / s, the formula will take the form: S2 = a * t ^ 2/2.

S2 = 1 m / s2 * (6 s) ^ 2/2 = 18 m.

S = 100 m + 18 m = 118 m.

Answer: the bus will be at a distance of S = 118 m from the intersection.