The bus driver drove for an hour at a speed of 100 km / h. Then he entered the motorway and increased the speed
The bus driver drove for an hour at a speed of 100 km / h. Then he entered the motorway and increased the speed by 20%. Having traveled at this speed for an hour, he felt tired and therefore reduced the speed by 20%. He drove at this speed for another 2 hours. Find the path covered by the bus in 4 hours.
t1 = 1 h.
V1 = 100 km / h.
t2 = 1 h.
V2 = V1 + 0.2 * V1.
t3 = 2 h.
V3 = V2 – 0.2 * V2.
S -?
The path of the S bus along the entire section will be the sum of the path of each section: S = S1 + S2 + S3.
Since the bus moved uniformly at each section, S1 = V1 * t1, S2 = V2 * t2 = (V1 + 0.2 * V1) t2, S3 = V3 * t3 = (V2 – 0.2 * V2) * t3 …
S1 = 100 km / h * 1 h = 100 km.
S2 = (100 km / h + 0.2 * 100 km / h) * 1 h = 120 km.
S3 = (120 km / h – 0.2 * 120 km / h) * 2 s = 192 km.
S = 100 km + 120 km + 192 km = 412 km.
Answer: the bus covered the distance S = 412 km, the bus moved for 2 hours at a speed of V3 = 96 km / h.