The bus moving at a speed of 50 km / h stood in front of the closed railway crossing for 1.5 minutes. At what speed should

The bus moving at a speed of 50 km / h stood in front of the closed railway crossing for 1.5 minutes. At what speed should he continue to move in order not to get out of the schedule, if the distance from the crossing to the nearest stop on the route is 3.75 km?

v = s / t -> s = vt t = s / v Let x be the distance -> t = sx / v (distance from the crossing, sometimes underline words for yourself, it helps a lot to understand the problem) s / v1 … v1 -I accepted a speed that supposedly “compensates” for your delay. I continue. s / v1 = s-vt / v -> v1 = v * s / s-vt Put everything you know into the formula (derived) and got the answer 75 km / h.
Answer: v1 = 75 km / h.