The bus, moving with constant acceleration a = 6m / s ^ 2, stops 2 s after the start of braking. Determine:

The bus, moving with constant acceleration a = 6m / s ^ 2, stops 2 s after the start of braking. Determine: a) the speed of the bus at the beginning of braking; b) the path taken by the bus to the stop.

We use the formula for uniformly accelerated movement: V = V0 + a * t.

Hence V0 = V – a * t = 0 – (-6) * 2 = 12 m / s – speed before braking.

We use the formula for the path with uniformly accelerated motion:

S = (V ^ 2 – V0 ^ 2) / (2 * a) = (0 ^ 2 – 12 ^ 2) / (2 * -6) = -114 / -12 = 12 m – the distance taken by the bus to the stop …