The bus traveled the first 30 km in 2000s, and the next 40 km in 1 hour. Find the average speed

The bus traveled the first 30 km in 2000s, and the next 40 km in 1 hour. Find the average speed for each section and for the entire route.

The average speed of movement in each section is calculated by the formula:
V = S / t, where S is the distance traveled, t is the bus travel time.
The first section of the path:
V1 = S1 / t1, where S1 = 30 km, t1 = 2000 s = 0.556 h.
V1 = S1 / t1 = 30 / 0.556 ≈ 54 km / h.
Second section of the path:
V2 = S2 / t2, where S2 = 40 km, t1 = 1 h.
V2 = S2 / t2 = 40/1 = 40 km / h.
Average speed all the way:
Vav. = (S1 + S2) / (t1 + t2) = (30 + 40) / (0.556 + 1) = 45 km / h.
Answer: V1 = 54 km / h, V2 = 40 km / h, Vav. = 45 km / h.