The bus weighing 13 tons moves evenly at a speed of 36 km / h. The friction coefficient is 0.03.
The bus weighing 13 tons moves evenly at a speed of 36 km / h. The friction coefficient is 0.03. Determine the current in the motor winding if the voltage is 600 V and the motor efficiency is 70%.
m = 13 t = 13000 kg.
V = 36 km / h = 10 m / s.
μ = 0.03.
U = 600 V.
Efficiency = 70%.
g = 10 m / s2.
I -?
Let’s write down the formula for the engine efficiency: efficiency = Ap * 100% / Az.
Ap = F * S, where F is the thrust force of the engine, S is the movement of the bus.
Since the bus moves uniformly in a straight line, the engine thrust force F is balanced by the friction force Ftr: F = Ftr.
The friction force Ftr is determined by the formula: Ftr = μ * m * g.
Ap = μ * m * g * S.
Az = I * U * t.
Efficiency = μ * m * g * S * 100% / I * U * t = μ * m * g * V * 100% / I * U.
The current I will be determined by the formula: I = μ * m * g * V * 100% / efficiency * U.
I = 0.03 * 13000 kg * 10 m / s2 * 10 m / s * 100% / 70% * 600 V = 928.5 A.
Answer: the current in the motor winding is I = 92.85 A.