The calorimeter contained 400 g of water at a temperature of 18 ° C. When a metal piece with a temperature of 60 ° C was lowered into the water. The temperature in the calorimeter was set at 20 ° C. The specific heat capacity of the metal from which the part is made is equal to …
mw = 400 g = 0.4 kg.
tv = 18 ° C.
td = 60 ° C.
t = 20 ° C.
md = 0.6 kg.
Sv = 4200 J / kg * ° C.
Qw = Qd.
The amount of heat Qw, which goes to heating water, is determined by the formula: Qw = Sv * mw * (t – tw).
The amount of heat Qd, which is released during the cooling of the part, is determined by the formula: Qd = Sd * md * (td – t).
Sv * mw * (t – tv) = sd * md * (td – t).
Sd = Sv * mw * (t – tv) / md * (td – t).
SD = 4200 J / kg * ° C * 0.4 kg * (20 ° C – 18 ° C) / 0.6 kg * (60 ° C – 20 ° C) = 140 J / kg * ° C.
Answer: the specific heat capacity of the part is Cd = 140 J / kg * ° C.
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