# The calorimeter contained 400 g of water at a temperature of 18 ° C. When a metal piece with a temperature of 60 °

**The calorimeter contained 400 g of water at a temperature of 18 ° C. When a metal piece with a temperature of 60 ° C was lowered into the water. The temperature in the calorimeter was set at 20 ° C. The specific heat capacity of the metal from which the part is made is equal to …**

mw = 400 g = 0.4 kg.

tv = 18 ° C.

td = 60 ° C.

t = 20 ° C.

md = 0.6 kg.

Sv = 4200 J / kg * ° C.

SD -?

Qw = Qd.

The amount of heat Qw, which goes to heating water, is determined by the formula: Qw = Sv * mw * (t – tw).

The amount of heat Qd, which is released during the cooling of the part, is determined by the formula: Qd = Sd * md * (td – t).

Sv * mw * (t – tv) = sd * md * (td – t).

Sd = Sv * mw * (t – tv) / md * (td – t).

SD = 4200 J / kg * ° C * 0.4 kg * (20 ° C – 18 ° C) / 0.6 kg * (60 ° C – 20 ° C) = 140 J / kg * ° C.

Answer: the specific heat capacity of the part is Cd = 140 J / kg * ° C.