The calorimeter contains water with a mass of 400 g, the temperature of 25 degrees will be what the water temperature

The calorimeter contains water with a mass of 400 g, the temperature of 25 degrees will be what the water temperature will be if the amount of heat is transferred to it 84 kJ.

Problem data: m (mass of water in the calorimeter) = 400 g (0.4 kg); t0 (water temperature before heat transfer) = 25 ºС; Q (the amount of heat transferred) = 84 kJ (84 * 10 ^ 3 J).

Reference values: Sv (specific heat capacity of water) = 4200 J / (kg * K).

The water temperature established in the calorimeter is determined from the formula: Q = Cw * m * (t – t0), whence t = Q / (Cw * m) + t0.

Calculation: t = 84 * 10 ^ 3 / (4200 * 0.4) + 25 = 75 ºС.

Answer: The water temperature in the calorimeter will be equal to 75 ºС.

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