The capacitor is connected to an alternating current circuit with a frequency of 200 Hz. The voltage in the circuit is 40V

The capacitor is connected to an alternating current circuit with a frequency of 200 Hz. The voltage in the circuit is 40V, the current is 0.63 A. What is the capacitance of the capacitor.

Given:
V = 200 Hz;
U = 40V;
I = 0.63A.
Find: C.
Decision:
You can find the capacitance of a capacitor using this formula:
C = U / (I * 2 * V) = 40 / (0.63 * 2 * 200) = 0.064F
Answer: 0.064