The capacitor with a capacity of 1.5 μF is included in the industrial AC network. Determine the capacitance of the capacitor.

The capacitance of a capacitor is determined by the formula:

XC = 1 / ω * C,

where XC is the capacitive resistance, ω is the cyclic frequency of the alternating current, C is the capacitance of the capacitor.

The relationship between the cyclic frequency of alternating current and the frequency (υ) is described by the formula:

ω = 2 * π * υ.

Given these two formulas, we get:

ХС = 1/2 * π * υ * С.

Since, the power frequency current, then υ = 50 (Hz).

Let’s calculate the XC:

XC = 1/2 * 3.4 * 50 * 1.5 * 10 ^ -6 = 10 ^ 6/471 = 0.00212 * 10 ^ 6 = 2.12 * 10 ^ 3 (Ohm) = 2.12 ( kOhm).

Answer: XC = 2.12 (kΩ)