The capacity of the capacitor is 20 microfarads, it is designed for 300 volts.

The capacity of the capacitor is 20 microfarads, it is designed for 300 volts. What is the energy of this capacitor? What is the amount of electric charge on its plates?

The energy of a charged capacitor can be easily determined by the formula:

W = C * U ^ 2/2, where C is the capacitance, U is the voltage across the capacitor. We substitute in this formula the values from the condition:

W = 20 * 10 ^ (- 6) * 300 ^ 2/2 = 10 ^ (- 5) * 9 * 10 ^ (4) = 0.9 J.

By definition of electrical capacity:

C = q / U, where q is charge, U is voltage. Then:

q = C * U = 20 * 10 ^ (- 6) * 300 = 6 * 10 ^ (- 3) Cl.

Answer: the required energy is 0.9 J, the charge is 6 * 10 ^ (- 3) C.



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