The capsule contains 0.15 mol of plutonium-239 isotope. Determine the activity of this isotope

The capsule contains 0.15 mol of plutonium-239 isotope. Determine the activity of this isotope if its half-life is 2.44 * 10 ^ 4 years.

To solve this problem, you need to use the following formula:
A = No * ln * 2 / T * (1/2);
Let’s transform the formula:
A = v * Na * ln * 2 / T * (1/2);
Substitute the values and calculate:
A = 0.15 * 6 * 10 ^ 23 * 0.69 / 2.44 / 10 ^ 4;
We get:
A = 0.25 * 10 ^ 19 Bq.
Answer: A = 0.25 * 10 ^ 19 Bq.