The car and the motorcyclist drove out simultaneously in the same direction at speeds of 75 km / h and 67 km / h.

| January 8, 2021 | education

The car and the motorcyclist drove out simultaneously in the same direction at speeds of 75 km / h and 67 km / h. How far did the motorcyclist travel when the car overtook him by 32 km?

1) Relative speed of a car and a motorcyclist (movement in one direction): ΔV = Va – Vm, where Va is the speed of the car (Va = 75 km / h), Vm is the speed of the motorcyclist (Vm = 67 km / h).
ΔV = Vа – Vm = 75 – 67 = 8 km / h.
2) The duration of the movement of the car and the motorcyclist: t = ΔS / ΔV, where ΔS is the distance between the car and the motorcyclist at the considered moment of time (ΔS = 32 km).
t = ΔS / ΔV = 32/8 = 4 h.
3) The distance that the motorcyclist had to travel: Sa = Vm * t = 67 * 4 = 268 km.
Answer: The motorcyclist had to travel 268 km.



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