The car drives past the observer, moving at a speed of 40 m / s. At this moment, the driver presses

The car drives past the observer, moving at a speed of 40 m / s. At this moment, the driver presses on the gas and the car begins to move with an acceleration modulo 4m / s2. How far will the car go in 6 seconds?

To find out the desired path covered by the presented car in 6 seconds, consider the formula: S = Vn * t + 0.5 * a * t ^ 2, where Vn is the speed before acceleration (Vn = 40 m / s); a – constant acceleration modulus (a = 4 m / s2); t – duration of acceleration of the presented vehicle (t = 6 s).

Let’s perform the calculation: S = Vn * t + 0.5 * a * t ^ 2 = 40 * 6 + 0.5 * 4 * 6 ^ 2 = 312 m.

Answer: In 6 seconds of acceleration, the presented car had to cover a distance of 312 m.