The car drove along a straight road for 300 meters, then turned to the right by 90 degrees and drove along a straight road

The car drove along a straight road for 300 meters, then turned to the right by 90 degrees and drove along a straight road for 300 meters. then he rode the shortest distance to the starting point. determine the total distance and displacement traveled by the car

Solution:

1. Since the car has turned 90 degrees, its trajectory can be described by an equilateral triangle. Its hypotenuse is (300 ^ 2 + 300 ^ 2) ^ 0.5 = (90,000 + 90,000) ^ 0.5 = 180,000 ^ 0.5 = 424.264 meters.

2. Find the path traveled by the car:

300 + 300 + 424.264 = 1024.264 meters;

3. Displacement is a vector connecting the starting position of the vehicle with the ending position. Since the car arrived at the starting point, its movement is 0.

Answer: the path is 1024.264 meters, the displacement is 0.



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