The car drove the first part of the journey (30 km) at a speed of 60 km / h. Then he increased his speed 1.5 times and overcame
| November 25, 2020 | education
The car drove the first part of the journey (30 km) at a speed of 60 km / h. Then he increased his speed 1.5 times and overcame the rest in 15 minutes. Find the average ground speed of the vehicle in km / h.
Time t1 for which the car traveled the first part of the journey: t1 = 30 km / 60 km / h = 0.5 h.
Speed in the second section: V2 = 60 km / h * 1.5 = 90 km / h.
The time during which the car traveled the second part of the journey in hours t2 = 15 min / (60 min / h) = 0.25 h.
The second section of the path S2 = V2 * t2 = 90 km / h * 0.25 h = 22.50 km.
The entire path S = 30 km + 22.5 km = 52.5 km.
Total travel time: t = t1 + t2 = 0.5 h + 0.25 h = 0.75 h.
Average speed Vc = 52.5 km / 0.75 h = 70 km / h.
Answer: 70 km / h.
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