The car drove through the first section of the route at a speed of 11 km / h, and the second at a speed of 40 km / h
The car drove through the first section of the route at a speed of 11 km / h, and the second at a speed of 40 km / h, and it took the same time to pass each of the sections. What is the average speed all the way?
V1 = 11 km / h.
V2 = 40 km / h.
t1 = t2.
Vav -?
To find the average vehicle speed Vav, it is necessary to divide the entire path S it has traveled by the time of its movement t: Vav = S / t.
The entire path S traveled by him will be the sum: S = S1 + S2, where S1 is the distance of the first section of the path, S2 is the distance of the second section of the path.
S1 = V1 * t1.
S2 = V2 * t2 = V2 * t1.
S = V1 * t1 + V2 * t1 = (V1 + V2) * t1.
The travel time of the entire path is expressed by the sum: t = t1 + t2, where t1 is the time of movement on the first section of the path, t2 is the time of movement on the second section of the path.
Since t1 = t2, then t = t1 + t1 = 2 * t1.
Vav = (V1 + V2) * t1 / 2 * t1 = (V1 + V2) / 2.
Vav = (11 km / h + 40 km / h) / 2 = 25.5 km / h.
Answer: the average vehicle speed was Vav = 25.5 km / h.