The car, having an initial speed V0, stopped in t-4 s after the start of braking with a constant modulus
The car, having an initial speed V0, stopped in t-4 s after the start of braking with a constant modulus of acceleration a -0.5 m / s. What distance did the car go during the braking time?
Let the car have an initial speed v₀. It stopped in t = 4 s after the start of braking with constant modulus of acceleration a = – 0.5 m / s ^ 2, that is, the final speed of the car v = 0 m / s.
To find what distance the car traveled during the braking time, you must first find its initial speed using the formula v = v₀ + a ∙ t.
Then v₀ = v – a ∙ t or v₀ = 0 – (- 0.5 m / s ^ 2) ∙ 4 s; v₀ = 2 m / s.
We will find the traversed path by the formula:
S = (v ^ 2 – v₀ ^ 2): (2 ∙ a) or
S = (0 ^ 2 – (2 m / s) ^ 2): (2 ∙ (- 0.5 m / s ^ 2)) = 4 m.
Answer: v₀ = 2 m / s; S = 4 m.